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agent: Continue to retry indefinitely (#3599)
When the woodpecker server is not reachable (eg. for update, maintenance, agent connection issue, ...) for a long period of time, the agent tries continuously to reconnect, without any delay. This creates **several GB** of logs in a short period of time. Here is a sample line, repeated indefinitely: ``` {"level":"error","error":"rpc error: code = Unavailable desc = connection error: desc = \"transport: Error while dialing: dial tcp x.x.x.x:xxx: connect: connection refused\"","time":"2024-04-07T17:29:59Z","message":"grpc error: done(): code: Unavailable"} ``` It appears that the [backoff package](https://pkg.go.dev/github.com/cenkalti/backoff/v4#BackOff), after a certain amount of time, returns `backoff.Stop` (-1) instead of a valid delay to wait. It means that no more retry should be made, [as shown in the example](https://pkg.go.dev/github.com/cenkalti/backoff/v4#BackOff). But the code doesn't handle that case and takes -1 as the next delay. This led to continuous retry with no delay between them and creates a huge amount of logs. [`MaxElapsedTime` default is 15 minutes](https://pkg.go.dev/github.com/cenkalti/backoff/v4#pkg-constants), passed this time, `NextBackOff` returns `backoff.Stop` (-1) instead of `MaxInterval`. This commit sets `MaxElapsedTime` to 0, [to avoid `Stop` return](https://pkg.go.dev/github.com/cenkalti/backoff/v4#ExponentialBackOff).
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@ -53,6 +53,7 @@ func (c *client) Close() error {
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func (c *client) newBackOff() backoff.BackOff {
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func (c *client) newBackOff() backoff.BackOff {
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b := backoff.NewExponentialBackOff()
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b := backoff.NewExponentialBackOff()
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b.MaxElapsedTime = 0
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b.MaxInterval = 10 * time.Second //nolint: gomnd
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b.MaxInterval = 10 * time.Second //nolint: gomnd
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b.InitialInterval = 10 * time.Millisecond //nolint: gomnd
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b.InitialInterval = 10 * time.Millisecond //nolint: gomnd
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return b
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return b
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