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Use relative list order ranking in openlibrary search

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Set OpenLibrary search condifidence based on the provided result order,
just using 1/(list index), so the first has rank 1, the second 0.5, the
third 0.33, et cetera.
This commit is contained in:
Mouse Reeve 2022-05-31 10:22:49 -07:00
parent 355e7039f0
commit 374fdcf467
1 changed files with 7 additions and 1 deletions
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8
bookwyrm/connectors/openlibrary.py
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@ -153,12 +153,17 @@ class Connector(AbstractConnector):
return f"{self.covers_url}/b/id/{image_name}"
def parse_search_data(self, data, min_confidence):
for search_result in data.get("docs"):
for idx, search_result in enumerate(data.get("docs")):
# build the remote id from the openlibrary key
key = self.books_url + search_result["key"]
author = search_result.get("author_name") or ["Unknown"]
cover_blob = search_result.get("cover_i")
cover = self.get_cover_url([cover_blob], size="M") if cover_blob else None
# OL doesn't provide confidence, but it does sort by an internal ranking, so
# this confidence value is relative to the list position
confidence = 1 / (idx + 1)
yield SearchResult(
title=search_result.get("title"),
key=key,
@ -166,6 +171,7 @@ class Connector(AbstractConnector):
connector=self,
year=search_result.get("first_publish_year"),
cover=cover,
confidence=confidence,
)
def parse_isbn_search_data(self, data):